Give examples of functions from $\mathbb
i. This is certainly injective because $(-x)^2$ will be unique for unique $x \in \mathbb^+$. However, it cannot be surjective since you aren't mapping onto any negative reals.
ii. That is certainly correct. $(-x)^2$ and $x^2$ will map to the same element, so the function is not injective. However, every element in $\mathbb^+$ has a square root, so it must be a surjective mapping to the non-negative reals.
iii. Is also correct. The problem with ii not being injective has been resolved by restricting the function's domain to the non-negative real numbers.
iv. Is correct. Certainly, it cannot be surjective since you aren't mapping onto the negative reals. It cannot be injective because $(-x)^2$ = $x^2$.
In short, you are partiallly correct. The only thing is that it looks like your problem statement requires your functions be defined as $f:\mathbb \rightarrow \mathbb$?